Fantastic 4 Data
Help on Chemical Composition and equilibrium constants?
The equilibrium constant for the reaction N2 (g) + 1/2O2 (g) <=> N2O (g) is 7.1×10 ^ -19 to 25 degrees (C). The equilibrium constant for the reaction N2 (g) + O2 (g) <=> 2NO (g) is 4.32×10 ^ -31 25 degrees (C). A. Given these data, which is the equilibrium constant for the reaction below 25 degrees (C)? N20 (g) + 1/2O2 (g) <=> 2NO (G) b. What is the value of Kc 25 degrees (C)? C. Assume the system is in equilibrium in a container of 1.000L, if the volume of container is now reduced to 0.500 L, what happens to the composition of the container? Any help on this would be just fantastic!
a. A. N2 (g) + 1/2O2 (g) <=> N2O (g )………. k1 = 7.1×10 ^ -19 B. N2 (g) + O2 (g) <=> 2NO (g) ……………. K2 = 4.32×10 ^ -31 C. N20 (g) + 1/2O2 (g) <=> 2NO (g )……….. k3 =? You have to handle the first two reactions so that when you add together they equal the overall reaction (C). How N2O one of the reactants in the reaction C and the reaction is the only reaction that contains N2O is a need to reverse the reaction A. We do not have to change some thing about the reaction B. N2O (g) <=> N2 (g) + 1/2O2 (gk = )…….. (1/7.1×10 ^ -19) (Since the reaction reversed had to reverse the equilibrium constant) So, now you add reactions A and B for C: A. N2O (g) <=> N2 (g) + 1/2O2 (g) B. N2 (g) + O2 (G) <=> 2NO (g) —————————————- —— —— C. N20 (g) + 1/2O2 (g) <=> 2NO (g )……. k3 = (1/k1) (k2) = 6.085 x 10 ^ -13 b. You need to use the relationship between kc and kp to find Kp Kc = Kc (RT) delta ^ (n) where n is the sum of stoichiometric coefficients gaseous products minus the sum of stoichiometric coefficients of gaseous reactants. I do not know what is kp. I think it is a constant that you should have been given. Research Kp and plug it in and solve. R is 8.314 j (k * mol) and T is 298K. n is 2 to 1.5 = 0.5 (I think!) c. In this matter of applying what you know about the Principle Le Chatelier. When you decrease the volume of the reaction vessel that you change the balance in the sense that it has the smallest number of moles of gas. Therefore, to the reaction N20 (g) + 1/2O2 (g) <=> 2NO (g if you lower the volume of the reaction vessel that you would change the balance to the left (Reactants) because there are 1.5 moles of gas left and two moles of gas on the right.
Iron Man TAS: Data In, Chaos Out (1/2)